I have a number of $ 23 for the loop.
For ($ page = 0; $ page & lt; $ count; $ page ++) {echo $ page; }
I want to substitute a page variable instead of one, rather than 10, so that when the $ page reverbs it, I want the result 10, 20, and not the last 23.
For ($ page = 0; $ page & lt; $ count; $ page + 10) {echo $ page; }
When I do this, the loop continues continuously, 0 resonates. If someone has any advice, I would appreciate it. thank you in advanced.
for ($ page = 0; $ page & lt; $ count; $ page + = 10) {echo $ page; }
Just your increment syntax should be slightly wrong (page + =
not page +
) which is not actually updated The value of $ page
var)
Alternatively you can use long form / more complex math:
for ( $ Page = 0; $ page & lt; $ count; $ page = $ page + 10) {$ page echo;
Word of caution Ensure that you have the status of any category ( & lt;
or & lt; = < / Code>) If you are resizing your step in this way, otherwise you can jump ahead of your situation (read
! = 23
) and create a never-ending loop Are there. There is no problem for the way you wrote it, but there is something to consider.
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