Using regex in python -

August 15, 2012

I have the following problem: I want to run away from all the special characters in a dragon string.

  str = 'efex-x? K =; - 're.sub ("([^ a-zA-Z0- 9])", r' \\ 1 ', str) eFEx \\ 1x \\ 1k \\ 1 \\ 1 \\ 1' str = 'Efex-x? K =; - 're Shab ("([^ A-zA-Z0- 9]), 'R' '1', str) 'eFEx-x? K =; -' re.sub (" ([^ a-zA-Z0- 9 I can not seem to win here '1' indicates the special character and I am going to this special character before I want to add '\', but using its \ 1 means its special meaning is removed and \\ 1 also does not help.    
  Use  r '\\\ 1' . It is a backslash (escaped, hence  \\ )  Verify by \ 1 . 
 
 
  For that it works, try: 
   str = 'eFEx-x? K =; -' print again. ("([^ A-zA-Z0- 9] ) ", R '\\\ 1', str)  
  It prints: 
   efex \ -x \? K \ = \; \ -  
  which I think you want. When interpreter output  'efex \\ - x \\? K \\ = \\ \\ - \' -  Do not be confused, double backslash is because interpreter gives it output quote, unless you use  print .


















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