Functions: {x * y such as SS & amp; Y is counting intersection, where S is something like this:
j = 0 [i * j for j ++ and i in s] [s1 * 1, s2 * 2, s3 * 3 ...]
For your edited question, you want
[i * j for j, i enumerate (s)] There is no ++ in dragon because it has a clear distinction between statements and expressions.
[i * j for i, calculation in j (xrange (60), start = 40]]
and then another method
[J * for I * j * (xrange (40, 100), xchange (60))] I think that is the best way to do this first because this function calls Reduces and is most readable.
In addition, if you do not know that you absolutely need a list, then use the generator expression
(for i + 40) * i (60)) in This will allow you to process the results at one time and will never store the entire list in memory. You can sum , Generator expressions can be found for accessories such as max , min and most other bilts.
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