regex - Regexp Java for password validation -


I am creating a regexp for password verification in the Java application as a configuration parameter.

is regexp: 

  ^. * (? =. * {0- 9]) (? =. * [AG]) (? =. * [AG]) (? =. * [@ # $%] ^ & Amp; + =]). * $

Password policy is:

    at least 8 characters

  • Less it

  • At least one lower alpha four letter and one upper alpha character

  • Includes a set of special characters There is at least one letter within ( @ #% $ ^ etc.)

  • This does not include location, tab, etc.

I can not find just 5 marks.

Can someone help me? >

Try this: 

  ^ (? =. * [0-9]) (? =. * [Az]) (? =? * [AZ]) (? =?. * [@ # $% ^ & Amp; + =]) (? = \ S + $) {8,} $

explanation: 

  ^ # start-string (? =. * [0-9]) # points at least one Times should be (? =. *. * [AG]) # should be at least once the letter (? =. * [AZ]) # At least once (============= =========================== At least once a special character should be at least once (? = \ S + $) # No white space is allowed, the entire string. {8,} # Anything, at least eight places, though $ # end-of-string

adding, modifying individual rules Easy to remove or delete, because each rule is an independent "module".

(? = =. * [Xyz]) Build the entire string (. * < / Code>) and the event behind where the [xyz] match can be successful, if it is found, if it is found to be [xyz] , otherwise it will fail

Optional will use a reluctant qualifier: (? =? *? [Xyz]) . To check the password, it will hardly make any difference, too long Time till date C it may be more efficient version.

The most efficient version (but the hardest to read and maintain, so prone to the most error) will be (? =? [^ Xyz] * [xyz]), , of course . For this length of a regex and for this purpose, I would dis-recommend that way, because it is not a real benefit.


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